7(x^2-4)+2x=2(x-4)

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Solution for 7(x^2-4)+2x=2(x-4) equation: 


Simplifying
7(x2 + -4) + 2x = 2(x + -4)

Reorder the terms:
7(-4 + x2) + 2x = 2(x + -4)
(-4 * 7 + x2 * 7) + 2x = 2(x + -4)
(-28 + 7x2) + 2x = 2(x + -4)

Reorder the terms:
-28 + 2x + 7x2 = 2(x + -4)

Reorder the terms:
-28 + 2x + 7x2 = 2(-4 + x)
-28 + 2x + 7x2 = (-4 * 2 + x * 2)
-28 + 2x + 7x2 = (-8 + 2x)

Add '-2x' to each side of the equation.
-28 + 2x + -2x + 7x2 = -8 + 2x + -2x

Combine like terms: 2x + -2x = 0
-28 + 0 + 7x2 = -8 + 2x + -2x
-28 + 7x2 = -8 + 2x + -2x

Combine like terms: 2x + -2x = 0
-28 + 7x2 = -8 + 0
-28 + 7x2 = -8

Solving
-28 + 7x2 = -8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 28 + 7x2 = -8 + 28

Combine like terms: -28 + 28 = 0
0 + 7x2 = -8 + 28
7x2 = -8 + 28

Combine like terms: -8 + 28 = 20
7x2 = 20

Divide each side by '7'.
x2 = 2.857142857

Simplifying
x2 = 2.857142857

Take the square root of each side:
x = {-1.690308509, 1.690308509}

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